Sum Root to Leaf Numbers
Given a binary tree containing digits from
0-9 only, each root-to-leaf path could represent a number.
An example is the root-to-leaf path
1->2->3 which represents the number 123.
Find the total sum of all root-to-leaf numbers.
For example,
1 / \ 2 3
The root-to-leaf path
The root-to-leaf path
1->2 represents the number 12.The root-to-leaf path
1->3 represents the number 13.
Return the sum = 12 + 13 =
25.
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
void sumNumbersInt(TreeNode *root, string path, int &pathSum)
{
if (!root)
return;
if (!root->left && !root->right)
{
path+=to_string(root->val);
pathSum+=atoi(path.c_str());
}
string currentPath = path + to_string(root->val);
sumNumbersInt(root->left, currentPath, pathSum);
sumNumbersInt(root->right, currentPath, pathSum);
}
public:
int sumNumbers(TreeNode *root)
{
int pathSum=0;
string path;
if (!root)
return 0;
if (!root->left && !root->right)
return root->val;
sumNumbersInt(root, path, pathSum);
return pathSum;
}
};
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